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Reflects change in model name.

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Elf M. Sternberg 2010-10-13 09:20:49 -07:00
parent ad68f0ee16
commit 6f116d2d15
1 changed files with 9 additions and 5 deletions
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@ -32,18 +32,22 @@ Standard Usage:
Find all the zipcodes within 50 miles: Find all the zipcodes within 50 miles:
target = Zipmap.objects.get(zipcode = zip_form.cleaned_data['zipcode1'].strip()) from zipdistance.models import ZipDistance
zips = Zipmap.objects.distance_from(target, 50) target = ZipDistance.objects.get(zipcode = zip_form.cleaned_data['zipcode1'].strip())
zips = ZipDistance.objects.distance_from(target, 50)
Find the distance between two zipcodes: Find the distance between two zipcodes:
zip1 = Zipmap.objects.get(zipcode = zip_form.cleaned_data['zipcode1'].strip()) from zipdistance.models import ZipDistance
zip2 = Zipmap.objects.get(zipcode = zip_form.cleaned_data['zipcode1'].strip()) zip1 = ZipDistance.objects.get(zipcode = zip_form.cleaned_data['zipcode1'].strip())
zip2 = ZipDistance.objects.get(zipcode = zip_form.cleaned_data['zipcode1'].strip())
zip1.distance_between(zip_2) zip1.distance_between(zip_2)
Find all the stores within a given distance. Find all the stores within a given distance.
zips = Zipmap.objects.distance_from(target, 50) from zipdistance.models import ZipDistance
from yourapp.models import Store
zips = ZipDistance.objects.distance_from(target, 50)
stores = Store.objects.get(zipcode__in = [z.zipcode for z in zips]) stores = Store.objects.get(zipcode__in = [z.zipcode for z in zips])
That last one's not terribly efficient. If you used the ZipMap as a That last one's not terribly efficient. If you used the ZipMap as a